Battle of attrition

From DDwiki
Revision as of 08:58, 31 January 2014 by Flap (Talk | contribs)

Jump to: navigation, search

Battle of attrition is the term used by Desktop Dungeons creators of define a fight when you are exploring mid-fight to gain resources. Another widespread term on the forum is regen-fighting.

As you will often want to fighter monster at an higher level than you are, they would often heal quicker than you. So knowing if you can do it is not always obvious. here are some tips to know when you can do it.

Not that you can read Annotated Playthrough: Regenfighting for more explanation.


Let's define :

  • Dh = damage caused by hero (in hitpoints, or hp)
  • Rh = point restored by hero per tile (in hitpoints/tile, or hp/t) (usually level of the hero)
  • Df = damage caused by fireball (hp)
  • Cf = number of tiles to cast a new fireball (usually, cost in manan) (t)
  • Dm = damage caused by the monster (hp)
  • Rm = point restored by the monster per tile explored (hp/t) (usually level of the monster, or level-1 if the monster is burning)

You have the total damage caused to the monster by the hero per tile (taking into account the regeneration) : Dt = (Dh*Rh - Dm(Rm - Df/Cf))/Dm (in hp/t)

So, you can regen fight if Dh*Rh > Dm(Rm -Df/Cf) If you decided not to cast fireballs, you can regen fight if Dh*Rh > Dm*Rm


Now, lets have a closer look at the formula: We have for both the monster and the hero a ratio emerging : Damages*Regeneration (in hp*hp/t), which we could call the hit-regeneration ratio. The higher, the more potent is the character in regen fighting (he strikes stronger than his opponent and/or regenerates quicker). However, when we take into account the fireball, the damages caused by the fireball per turn (ratio Df/Cf) reduces the regeneration per tile (Rm) of the monster, hence that new value "Dm(Rm-Df/Cf)" for the hit-regeneration ratio of the monster.

Finally, the number of tile required to kill the monster in regen fighting would be : with T = number of tiles required to kill the monster (t) H = health of the monster (hp) T = H/Dt or T = H*Dm/(Rh*Dh-Dm(Rm-Df/Cf)) (in t)

For efficient regen fighting, for H, we should consider the remaining health of the monster once the hero has used its full stock of health and mana for the original strikes (before starting the regeneration). This the higher max health and mana, the less tile you will use for the regeneration part of the fight.

Also, note that every damages should be adapted with the opponent's resistance, player's glyph and so on.